Welcome to MathMonsoon, a blog for people interested in math.
Feel free to share math problems or questions you may have happened upon, as well as any other mathematical thoughts. (Jokes are encouraged.)
Here's a formula I discovered while toying with the Fibonacci sequence:
If F(n) = F(n-1) + F(n-2), [the Fibonacci sequence], F(2n+1)^2 = {F(n)F(n+3)}^2 + {2F(n+1)F(n+2)}^2. In other words, any four consecutive Fibonacci numbers can be arranged to form a Pythagorean triple- the product of the first and last make the first number in the triple, the product of 2, the second and the third make the second number in the triple, and the third number in the triple with be the 2n+1st Fibonacci number (if the first number of the 4 consecutive numbers is the nth Fibonacci number).
I've got more up my sleeve but that's it for now.
Enjoy!
1 comment:
dear jacob, the fact you were doing this when you were a frosh proves that you are either non-human or amazingly amazing.
i've complimented you thrice today, so accept my damn friend request.
ps i think i might beat you one of these days in ping pong if you keep showing me spin tricks.
Post a Comment